The electric flux passing through the cube fo | vedclass

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Question

$\phi  = \frac{{{{m{q}}_{{m{net}}}}}}{{{ \in _0}}}$

for a charge placed at corner of cube

$\phi=\frac{q_{	ext {net }}}{8 \in_{0}}$

Vedclass · Accepted Answer

$\phi  = \frac{{ - 1}}{{2{ \in _0}}}$

Vedclass · Answer

$\phi  = \frac{{{{m{q}}_{{m{net}}}}}}{{{ \in _0}}}$

for a charge placed at corner of cube

$\phi=\frac{q_{	ext {net }}}{8 \in_{0}}$

$	herefore $ thus for given system

$\phi  = \frac{{(1 - 2 + 3 - 4 - 6 + 7 + 5 - 8)}}{{8{ \in _0}}}$

$\phi  = \frac{{ - 1}}{{2{ \in _0}}}$

The electric flux passing through the cube for the given arrangement of charges placed at the corners of the cube (as shown in the figure) is

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